Exact Solutions of the Paraxial Wave Dynamical Model
in Kerr Media with Truncated M-fractional Derivative
using the (G/G, 1/G)-Expansion Method
PIM MALINGAM1..
ID , PAIWAN WONGSASINCHAI1..
ID , SEKSON SIRISUBTAWEE2,3..
ID,
SANOE KOONPRASERT2,3..
ID
1Department of Mathematics, Faculty of Science and Technology
Rambhai Barni Rajabhat University, Chanthaburi 22000,
THAILAND
2Department of Mathematics, Faculty of Applied Science
King Mongkut's University of Technology North Bangkok, Bangkok 10800,
THAILAND
3Centre of Excellence in Mathematics, CHE, Si Ayutthaya Road, Bangkok 10400,
THAILAND
Abstract: The main purpose of this article is to use the (G/G, 1/G)-expansion method to derive exact traveling
wave solutions of the paraxial wave dynamical model in Kerr media in the sense of the truncated M-fractional
derivative. To the best of the authors’ knowledge, the solutions of the model obtained using the expansion method
are reported here for the first time. The exact solutions are complex-valued functions expressed in terms of
hyperbolic, trigonometric, and rational functions. In order to show the physical interpretations of the solutions,
the magnitude of selected solutions is plotted in 3D, 2D, and contour plots for a range of values of the fractional-
order of the equation. With the aid of a symbolic software package, all of the obtained solutions are substituted
back into the relevant equation to verify their correctness. Obtaining the results by this technique confirms the
strength and efficacy of the method for generating a variety of exact solutions of the problems arising in applied
sciences and engineering.
Key-Words: - Exact solutions, Paraxial wave dynamical model, Kerr media, (G/G, 1/G)-expansion method,
Truncated M-fractional derivative, Anti-soliton solution.
Received: February 26, 2023. Revised: November 23, 2023. Accepted: December 11, 2023. Published: December 31, 2023.
these dates in case of final acceptance, following strictly our data base and possible email
communication).
1 Introduction
Many physical phenomena arising in nature can
be modeled by nonlinear partial differential equa-
tions (NPDEs). For example, NPDEs have been
used as models in mechanics, [1], fiber optics, [2],
oceanography, [3], acoustics, [4], biology, [5], and
finance, [6]. Hence, finding solutions of NPDEs
has become important for modeling many real-world
problems. In particular, finding efficient techniques
for deriving exact traveling wave solutions of NPDEs
has attracted the interest of many researchers. Ef-
ficient methods that have been developed for ex-
tracting exact solutions of NPDEs include the mod-
ified (G/G2)-expansion method, [7], the extended
generalized (G/G)-expansion method, [8], the tanh-
coth method, [9], the Bäcklund transformations, [10],
the F-expansion method, [11], the modified auxil-
iary equation method, [12], and the two-variables
(G/G, 1/G)-expansion method, [13].
One of the interesting PDEs in applied sciences
and engineering is the paraxial wave dynamical equa-
tion model for transmission of light through optical
fibers of Kerr media, [14], [15], [16], [17]. This
model can be used to explain wave dynamics in
optical fibers. This behavior includes optical soli-
tons consisting of non-diffractive spatiotemporal and
non-dispersive localized wave packets which transmit
through the fiber. The paraxial wave equation in Kerr
media can be written as, [15], [16], [17], [18],
iW
y +f
2
2W
t2+g
2
2W
x2+k|W|2W= 0,(1)
where W=W(x, y, t)is the Kerr term which rep-
resents the bound of the complex wave, and f, g, k
are real constants. Eq. (1) for a monochromatic beam
is equivalent to the nonlinear Schrödinger equation
(NLSE) of a quantum particle. If f, g in Eq. (1)
are such that fg < 0, Eq. (1) becomes a hyper-
bolic NLSE but if fg > 0, then Eq. (1) becomes
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an elliptic NLSE. In recent years, equation (1) has
been solved using various analytical methods for its
exact traveling wave solutions as follows. In [15]
the authors obtained solitons, elliptic function, and
other solutions of Eq. (1) via utilizing three analyti-
cal techniques, namely, the improved simple equation
method, the exp(Φ(ζ))-expansion method and the
modified extended direct algebraic technique. Dis-
tinct types of structures for the obtained solutions
were depicted graphically. According to [16] some
singular, periodic, solitary wave, and rational so-
lutions of Eq. (1) were established using the Sar-
dar subequation method (SSM). The modulus, real
and imaginary plots of the solutions were demon-
strated for manifold implementations in many re-
search fields. In [17] the modified extended map-
ping technique was employed to assemble the soli-
tons, solitary waves, and rational solutions for Eq. (1).
The stability of Eq. (1) was studied via using modula-
tional instability (MI) analysis from which all soliton
solutions of the equation were verified to be stable and
exact. Moreover, the ϕ6model expansion technique
was utilized to obtain dark, bright, singular, bright-
dark, and periodic solitons for Eq. (1) as discussed
in [18]. The obtained solutions were expressed in
the form of trigonometric, hyperbolic, and exponen-
tial functions. In addition, a recent literature review
for solving Eq. (1) by using other different techniques
and solving the fractional complex paraxial wave dy-
namical model with Kerr media in the sense of the
conformable fractional derivative with respect to time
can be found in [19], and, [20], respectively.
However, a truncated M-fractional derivative,
[21], [22], [23], has recently attracted considerable
attention from many research scholars. Many par-
tial differential equations equipped with the truncated
M-fractional derivatives have been solved for their
exact traveling wave solutions which can be found
in [24], [25], [26], [27], [28]. An application of such
a derivative to the paraxial wave equation in Kerr me-
dia for formulating a novel equation is our major mo-
tivation. Consequently, it is very interesting to obtain
exact solutions of the resulting equation.
In this article, we adapt Eq. (1) by replacing its
classical partial derivatives with the truncated M-
fractional derivatives. The new equation can be writ-
ten as:
imβ
M,yW+f
2mβ
M,t mβ
M,tW
+g
2mβ
M,x mβ
M,xW+k|W|2W= 0,
0< β 1,
(2)
where mβ
M,x,mβ
M,y and mβ
M,t are the truncated M-
fractional partial derivatives of order βwith respect
to x, y, and t, respectively, which will be defined
in section 2. The main aim of this paper is to use
the (G/G, 1/G)-expansion method to extract exact
traveling wave solutions of Eq. (2) so that new solu-
tions and their physical behaviors are revealed here
for the first time. The remaining parts of this article
are organized as follows. Section 2 includes the defi-
nition of the truncated M-fractional derivative and its
characteristics. The main steps of the (G/G, 1/G)-
expansion method are also described in this section.
The application of the expansion method to Eq. (2) is
described in section 3. Graphical representations of
chosen exact solutions are shown in section 4. The
conclusions of this research are discussed in the final
section.
2 Methoddology
In this section, a definition of the truncated M-
fractional derivative, its important properties and a
description of the (G/G, 1/G)-expansion method
are presented. They are required for constructing ex-
act traveling wave solutions of Eq. (2).
2.1 Truncated M-fractional derivative and
its properties
Definition 2.1 The truncated Mittag-Leffler function
with one parameter is defined as, [21], [22], [23],
mEγ(z) =
m
n=0
zn
Γ(γn + 1),(3)
where γ > 0and zC.
Definition 2.2 Let f: [0,)Rbe a function.
Then, the truncated M-fractional derivative of fof
order βis defined by, [21], [22], [23],
mDβ
M,tf(t) = lim
τ0
ftmEγ(τtβ)f(t)
τ,(4)
where 0< β 1and γ > 0. If the limit in (4) ex-
ists, then we say that the function fis β-truncated M-
fractional differentiable, or shortly, β-differentiable.
Moreover, if fis β-differentiable on (0, a), a >
0and limt0+mDβ
M,tf(t)exists, then we define
mDβ
M,tf(0) = limt0+mDβ
M,tf(t).Some use-
ful properties of the truncated M-fractional derivative
are as follows, [21], [25], [29], [30], [31], [32]. Let
f(t), g(t)be β-differentiable functions for all t > 0,
β(0,1],and γ > 0. Then, we have
(1) mDβ
M,t(λ) = 0,λR.
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(2) mDβ
M,t(af(t) + bg(t)) = amDβ
M,tf(t)
+bmDβ
M,tg(t),a, b R.
(3) mDβ
M,t (f(t)g(t)) = f(t)mDβ
M,tg(t)
+g(t)mDβ
M,tf(t).
(4) mDβ
M,t f(t)
g(t)
=g(t)mDβ
M,tf(t)f(t)mDβ
M,tg(t)
(g(t))2,
where g(t)= 0.
(5) mDβ
M,t(fg)(t) = f(g(t))mDβ
M,tg(t)
when fis differentiable at g(t).
(6) If, in addition, fis differentiable,
then mDβ
M,t(f(t)) = t1β
Γ(γ+1)
df(t)
dt .
Utilizing the definition 2.2, the truncated M-fractional
partial derivative of u=u(x, t)with respect to t > 0
of order β(0,1] is defined as
mβ
M,tu(x, t)
= lim
τ0
ux, t mEγ(τtβ)u(x, t)
τ.
(5)
2.2 The (G/G, 1/G)-expansion Method
Consider the following nonlinear partial differential
equation in three independent variables t, x, and y:
Fu, mα,γ
M,tu, mβ
M,xu, mδ,γ
M,yu, mα,γ
M,t mβ
M,xu,
mα,γ
M,t mδ,γ
M,yu,mβ
M,x mδ,γ
M,yu, ...= 0,
(6)
where 0< α, β, δ 1,and mα,γ
M,tu, mβ
M,xu, and
mδ,γ
M,yuare the truncated M-fractional partial deriva-
tives of a dependent variable uwith respect to inde-
pendent variables t, x, and y.Fis a polynomial of
the unknown function u=u(x, y, t)and its various
partial derivatives in which the highest order deriva-
tives and nonlinear terms are involved. Employing
the following traveling wave transformation, [30]
u(x, y, t) = U(ξ),
ξ= Γ(γ+ 1) kxβ
β+lyδ
δ+ctα
α+d,(7)
where k, l, c, and dare constants to be determined
later, we can reduce Eq. (6) to the following ODE in
U=U(ξ):
P(U, U, U′′, . . .) = 0,(8)
where Pis a polynomial of U(ξ)and its various
derivatives in which the prime notation ()repre-
sents the derivative with respect to ξ. Before we can
provide the key steps of the (G/G, 1/G)-expansion
method, it is necessary to give the following informa-
tion, [13], [33], [34], [35], [36]. Consider the follow-
ing second-order linear ODE:
G′′(ξ) + λG(ξ) = µ, (9)
where λ, µ are constants. Denoting the functions ϕ
and ψas
ϕ(ξ) = G(ξ)
G(ξ), ψ(ξ) = 1
G(ξ),(10)
we can transform equations (9) and (10) into the fol-
lowing system of two nonlinear ordinary differential
equations
ϕ=ϕ2+µψ λ, ψ=ϕψ. (11)
The solutions of Eq. (9) can be separated into the fol-
lowing three cases.
Case 1: If λ < 0,then the general solution of (9) is
of the form
G(ξ) = A1sinh ξλ
+A2cosh ξλ+µ
λ,
(12)
and we have the following relationship
ψ2=λ
λ2σ1+µ2ϕ22µψ +λ,(13)
where A1and A2are arbitrary constants and σ1=
A2
1A2
2.
Case 2: If λ > 0,then the general solution of (9) can
be written as
G(ξ) = A1sin(ξλ) + A2cos ξλ+µ
λ,(14)
and we have the following associated relation
ψ2=λ
λ2σ2µ2ϕ22µψ +λ,(15)
where A1and A2are arbitrary constants and σ2=
A2
1+A2
2.
Case 3: If λ= 0,then the general solution of (9) can
be displayed as
G(ξ) = µ
2ξ2+A1ξ+A2,(16)
and the corresponding relation is
ψ2=1
A2
12µA2ϕ22µψ,(17)
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where A1and A2are arbitrary constants.
The main steps of the (G/G, 1/G)-expansion
method, [13], [33], [34], [35], [36], can be described
as follows.
Step 1. Assume that the solution to Eq. (8) can be
expressed in terms of a polynomial of the two vari-
ables ϕand ψas follows
U(ξ) = a0+
N
j=1
ajϕj+
N
j=1
bjϕj1ψ, (18)
where a0, aj,and bj, j = 1,2, . . . , N, are constants
to be found later with a2
N+b2
N= 0 and where the
functions ϕ=ϕ(ξ)and ψ=ψ(ξ)are implicitly as-
sociated to Eq. (9) through the relations in Eq. (10).
Step 2. We determine the value of the positive
integer Nin Eq. (18) by balancing the highest order
derivative and the nonlinear terms in Eq. (8). Denot-
ing the degree of U(ξ)by Deg[U(ξ)] = N, we can
calculate the degree of other terms in the equation us-
ing the following relations
Deg dqU(ξ)
q=N+q,
Deg (U(ξ))pdqU(ξ)
qs=N p +s(N+q).
(19)
Step 3. Replacing the solution form (18) with
the known value of Ninto Eq. (8) with the assistance
of Eq. (11) and Eq. (13), we can convert the function
Pin Eq. (8) into a polynomial in ϕand ψin which
the degree of ψis one. Equating each coefficient
of the resulting polynomial to zero, we obtain a sys-
tem of algebraic equations. These algebraic equations
can then be solved using the Maple software pack-
age to obtain values for the unknowns a0, aj, bj, j =
1,2, . . . , N, k, l, c, d, µ, λ(<0).Therefore, the exact
solutions of Eq. (6) can be obtained in terms of hyper-
bolic functions by using Eq. (12) and the transforma-
tion in Eq. (7).
Step 4. Similar to Step 3, substituting the result
from Eq. (18) into Eq. (8) with the aid of Eq. (11) and
Eq. (15) for λ > 0, we can obtain the exact solutions
of Eq. (6) by using the transformation (7). The ob-
tained exact solutions in this step are written in terms
of trigonometric functions.
Step 5. In the same manner as Step 3, substituting
the result from Eq. (18) into Eq. (8) with the aid of
Eq. (11) and Eq. (17) for λ= 0, we can obtain the
traveling wave solutions of Eq. (6) with the help of
the transformation (7). The resulting exact solutions
in this step are obtained in terms of rational functions.
Remark 1: Particularly, if the balance number N
in Step 2 is not a positive integer, then some special
transformations must be applied for U(ξ)in (8) so that
the equation (8) can be converted into a new equation
of a new variable. For example, if N=q
pis a fraction
in the lowest terms, then U(ξ) = Vq
p(ξ)is inserted in
(8). Consequently, the new equation, written in terms
of V(ξ), has a positive integer balance number, [37].
Remark 2: When applied, the (G/G, 1/G)-
expansion method can provide three types of exact
solutions including hyperbolic, trigonometric, and ra-
tional function solutions.
Remark 3: The (G/G, 1/G)-expansion method
can be reduced to the (G/G)-expansion method by
some special setting, [37]. Thus, the (G/G, 1/G)-
expansion method is more effective and more general
than the (G/G)-expansion method.
3 Implementation of the
(G/G, 1/G)-expansion Method
In this section, we obtain exact traveling wave solu-
tions of Eq. (2) by using the (G/G, 1/G)-expansion
method. First, we assume that the exact solution of
(2) has the form
W(x, y, t) = U(χ)e ,(20)
where Uis a real-valued function of χ,i=1,and
χ=Γ(γ+ 1)
β(d1xβ+d2yβ+ρtβ),
ξ=Γ(γ+ 1)
β(s1xβ+s2yβ+τtβ+ω),
(21)
where d1, d2, ρ, s1, s2, τ, and ωare real constants,
the order 0< β 1,and the parameter γ > 0.
Substituting the solution form (20) into the proposed
problem (2) and then separating the real and imagi-
nary parts of the resulting equation, we obtain the fol-
lowing equations:
Re: fρ2+gd2
1U′′ (χ)fτ 2+gs2
1+ 2 s2U(χ)
+2 kU3(χ) = 0,(22)
Im: (d2+fρ τ +gd1s1)U(χ)=0.(23)
Since U(χ)in Eq. (23) is not zero, we have
d2=(fρ τ +gd1s1).(24)
Next, balancing the terms U′′ and U3in Eq. (22) via
the formulas in (19), we obtain N= 1 and the solu-
tion form of Eq. (22) is then
U(χ) = a0+a1ϕ(χ) + b1ψ(χ),(25)
where a0,a1,and b1are constant coefficients which
will be determined later such that a2
1+b2
1= 0.As
explained in equations (12), (14), and (16), there are
three cases for the functions ϕ(χ)and ψ(χ)in (25)
depending on the sign of λ.
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Case 1 (Hyperbolic function solutions): If λ < 0,
we substitute Eq.(25) with Eqs.(11) and (13) into
Eq.(22) and then the left-hand side of Eq. (22) be-
comes a polynomial in ϕ(χ)and ψ(χ). Setting all of
the coefficients of this resulting polynomial to zero,
we obtain the following system of nonlinear algebraic
equations in λ, µ, ω, ρ, τ, a0, a1, b1, d1, s1,and s2:
ϕ3: 2 fλ4ρ2A4
1a14fλ4ρ2A2
1A2
2a1
+ 2 fλ4ρ2A4
2a1+ 2 gλ4A4
1a1d2
1
4gλ4A2
1A2
2a1d2
1+ 2 gλ4A4
2a1d2
1
+ 2 kλ4A4
1a3
14kλ4A2
1A2
2a3
1
+ 2 kλ4A4
2a3
1+ 4 fλ2µ2ρ2A2
1a1
4fλ2µ2ρ2A2
2a1+ 4 gλ2µ2A2
1a1d2
1
4gλ2µ2A2
2a1d2
1+ 4 kλ2µ2A2
1a3
1
4kλ2µ2A2
2a3
16kλ3A2
1a1b2
1
+ 6 kλ3A2
2a1b2
1+ 2 fµ4ρ2a1
+ 2 gµ4a1d2
1+ 2 kµ4a3
16kλ µ2a1b2
1
= 0,
ϕ2: 6 4A4
1a0a2
112 kλ4A2
1A2
2a0a2
1
+ 6 kλ4A4
2a0a2
1+fλ3µ ρ2A2
1b1
fλ3µ ρ2A2
2b1+gλ3µ A2
1b1d2
1
gλ3µ A2
2b1d2
1+ 12 kλ2µ2A2
1a0a2
1
12 kλ2µ2A2
2a0a2
16kλ3A2
1a0b2
1
+ 6 kλ3A2
2a0b2
1+fλ µ3ρ2b1
+gλ µ3b1d2
1+ 6 kµ4a0a2
14b3
1λ2kµ
6kλ µ2a0b2
1= 0,
ϕ2ψ: 2 fλ4ρ2A4
1b14fλ4ρ2A2
1A2
2b1
+ 2 fλ4ρ2A4
2b1+ 2 gλ4A4
1b1d2
1
4gλ4A2
1A2
2b1d2
1+ 2 gλ4A4
2b1d2
1
+ 6 kλ4A4
1a2
1b112 kλ4A2
1A2
2a2
1b1
+ 6 kλ4A4
2a2
1b1+ 4 fλ2µ2ρ2A2
1b1
4fλ2µ2ρ2A2
2b1+ 4 gλ2µ2A2
1b1d2
1
4gλ2µ2A2
2b1d2
1+ 12 kλ2µ2A2
1a2
1b1
12 kλ2µ2A2
2a2
1b12kλ3A2
1b3
1
+ 2 kλ3A2
2b3
1+ 2 fµ4ρ2b1+ 2 gµ4b1d2
1
+ 6 kµ4a2
1b12kλ µ2b3
1= 0,
ϕ: 2 fλ5ρ2A4
1a14fλ5ρ2A2
1A2
2a1
+ 2 fλ5ρ2A4
2a1+ 2 gλ5A4
1a1d2
1
4gλ5A2
1A2
2a1d2
1+ 2 gλ5A4
2a1d2
1
fλ4τ2A4
1a1+ 2 fλ4τ2A2
1A2
2a1
fλ4τ2A4
2a1gλ4A4
1a1s2
1
+ 2 gλ4A2
1A2
2a1s2
1gλ4A4
2a1s2
1
+ 6 kλ4A4
1a2
0a112 kλ4A2
1A2
2a2
0a1
+ 6 kλ4A4
2a2
0a1+ 4 fλ3µ2ρ2A2
1a1
4fλ3µ2ρ2A2
2a1+ 4 gλ3µ2A2
1a1d2
1
4gλ3µ2A2
2a1d2
12fλ2µ2τ2A2
1a1
+ 2 fλ2µ2τ2A2
2a12gλ2µ2A2
1a1s2
1
+ 2 gλ2µ2A2
2a1s2
16kλ4A2
1a1b2
1
+ 6 kλ4A2
2a1b2
1+ 12 kλ2µ2A2
1a2
0a1
12 kλ2µ2A2
2a2
0a12λ4A4
1a1s2
+ 4 λ4A2
1A2
2a1s22λ4A4
2a1s2
+ 2 fλ µ4ρ2a1+ 2 gλ µ4a1d2
1
fµ4τ2a1gµ4a1s2
16kλ2µ2a1b2
1
+ 6 kµ4a2
0a14λ2µ2A2
1a1s2
+ 4 λ2µ2A2
2a1s22µ4a1s2= 0,
ϕψ :3fλ4µ ρ2A4
1a1+ 6 fλ4µ ρ2A2
1A2
2a1
3fλ4µ ρ2A4
2a13gλ4µ A4
1a1d2
1
+ 6 gλ4µ A2
1A2
2a1d2
13gλ4µ A4
2a1d2
1
+ 12 kλ4A4
1a0a1b124 kλ4A2
1A2
2a0a1b1
+ 12 kλ4A4
2a0a1b16fλ2µ3ρ2A2
1a1
+ 6 fλ2µ3ρ2A2
2a16gλ2µ3A2
1a1d2
1
+ 6 gλ2µ3A2
2a1d2
1+ 12 kλ3µ A2
1a1b2
1
12 kλ3µ A2
2a1b2
1+ 24 kλ2µ2A2
1a0a1b1
24 kλ2µ2A2
2a0a1b13fµ5ρ2a1
3gµ5a1d2
1+ 12 kλ µ3a1b2
1
+ 12 kµ4a0a1b1= 0,
ψ:fλ5ρ2A4
1b12fλ5ρ2A2
1A2
2b1
+fλ5ρ2A4
2b1+gλ5A4
1b1d2
1
2gλ5A2
1A2
2b1d2
1+gλ5A4
2b1d2
1
fλ4τ2A4
1b1+ 2 fλ4τ2A2
1A2
2b1
fλ4τ2A4
2b1gλ4A4
1b1s2
1
+ 2 gλ4A2
1A2
2b1s2
1gλ4A4
2b1s2
1
+ 6 kλ4A4
1a2
0b112 kλ4A2
1A2
2a2
0b1
+ 6 kλ4A4
2a2
0b12fλ2µ2τ2A2
1b1
+ 2 fλ2µ2τ2A2
2b12gλ2µ2A2
1b1s2
1
+ 2 gλ2µ2A2
2b1s2
12kλ4A2
1b3
1
+ 2 kλ4A2
2b3
1+ 12 kλ3µ A2
1a0b2
1
12 kλ3µ A2
2a0b2
1+ 12 kλ2µ2A2
1a2
0b1
12 kλ2µ2A2
2a2
0b12λ4A4
1b1s2
+ 4 λ4A2
1A2
2b1s22λ4A4
2b1s2
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fλ µ4ρ2b1gλ µ4b1d2
1fµ4τ2b1
gµ4b1s2
1+ 6 kλ2µ2b3
1+ 12 kλ µ3a0b2
1
+ 6 kµ4a2
0b14λ2µ2A2
1b1s2
+ 4 λ2µ2A2
2b1s22µ4b1s2= 0,
ϕ0:fλ4τ2A4
1a0+ 2 fλ4τ2A2
1A2
2a0
fλ4τ2A4
2a0gλ4A4
1a0s2
1
+ 2 gλ4A2
1A2
2a0s2
1gλ4A4
2a0s2
1
+ 2 kλ4A4
1a3
04kλ4A2
1A2
2a3
0
+ 2 kλ4A4
2a3
0+fλ4µ ρ2A2
1b1
fλ4µ ρ2A2
2b1+gλ4µ A2
1b1d2
1
gλ4µ A2
2b1d2
12fλ2µ2τ2A2
1a0
+ 2 fλ2µ2τ2A2
2a02gλ2µ2A2
1a0s2
1
+ 2 gλ2µ2A2
2a0s2
16kλ4A2
1a0b2
1
+ 6 kλ4A2
2a0b2
1+ 4 kλ2µ2A2
1a3
0
4kλ2µ2A2
2a3
02λ4A4
1a0s2
+ 4 λ4A2
1A2
2a0s22λ4A4
2a0s2
+fλ2µ3ρ2b1+gλ2µ3b1d2
1
fµ4τ2a0gµ4a0s2
14b3
1λ3kµ
6kλ2µ2a0b2
1+ 2 kµ4a3
0
4λ2µ2A2
1a0s2+ 4 λ2µ2A2
2a0s2
2µ4a0s2= 0.
(26)
Solving the above algebraic system using the Maple
package program, we get the following results.
Result 1
λ=λ, µ = 0, ω =ω, ρ =ρ, τ =τ, a0= 0,
a1=±fρ2+gd2
1
k, b1= 0, d1=d1,
d2=(fρ τ +gd1s1), s1=s1,
s2=fλ ρ2+gλ d2
1fτ2
2gs2
1
2,
(27)
where λ(<0), f, g, k, d1, ρ, s1, τ, ω are arbitrary
constants such that kfρ2+gd2
1<0. From Eqs.
(12), (20), (25), and (27), we get the solution of Eq.
(2) as:
W(x, y, t) =
±fρ2+gd2
1
kA1cosh χλλ+A2sinh χλλ
A1sinh χλ+A2cosh χλ
×e,
(28)
where A1, A2arbitrary constants and
χ=Γ(γ+ 1)
βd1xβ(fρ τ +gd1s1)yβ+ρ tβ,
ξ=Γ(γ+ 1)
βs1xβ+fλ ρ2+gλ d2
11
2fτ 21
2gs2
1yβ+τtβ+ω.
Result 2
λ=kb2
1
fρ2+gd2
1σ1
, µ = 0, ω =ω,
ρ=ρ, τ =τ, a0= 0, a1= 0, b1=b1,
d1=d1, d2=(fρ τ +gd1s1),
s1=s1, s2=σ1fτ2+gs2
1+kb2
1
2σ1
,
(29)
where σ1=A2
1A2
2and f, g, k, d1, ρ, s1, τ, ω, b1,
A1, A2are arbitrary constants such that λ < 0. From
Eqs. (12), (20), (25), and (29), we obtain the exact
solution of Eq. (2) as follows:
W(x, y, t) =
b1
A1sinh χλ+A2cosh χλ×e,
(30)
where
χ=Γ(γ+ 1)
βd1xβ(fρ τ +gd1s1)yβ+ρ tβ,
ξ=Γ(γ+ 1)
βs1xβσ1f τ 2+gs2
1+kb2
1
2σ1yβ+τtβ+ω.
Result 3
λ=4kb2
1
σ1fρ2+gd2
1, µ = 0, ω =ω, ρ =ρ,
τ=τ, a0= 0, a1=±fρ2+gd2
1
4k,
b1=b1, d1=d1, d2=(fρ τ +gd1s1), s1=s1,
s2=σ1fτ2+gs2
12kb2
1
2σ1
,
(31)
where σ1=A2
1A2
2and f, g, k, d1, ρ, s1, τ, ω, b1,
A1, A2are arbitrary constants such that λ < 0and
kfρ2+gd2
1<0. From Eqs. (12), (20), (25), and
(31), we obtain the exact solution of Eq. (2) as fol-
lows:
W(x, y, t) =
±fρ2+gd2
1
4kA1cosh χλλ+A2sinh χλλ
A1sinh χλ+A2cosh χλ+µ
λ
+b1
A1sinh χλ+A2cosh χλ+µ
λ×e ,
(32)
where
χ=Γ(γ+ 1)
βd1xβ(fρ τ +gd1s1)yβ+ρ tβ,
ξ=Γ(γ+ 1)
βs1xβσ1f τ 2+gs2
12kb2
1
2σ1yβ+τtβ+ω.
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Result 4
λ=λ, µ =µ, ω =ω, ρ =ρ, τ =τ, a0= 0,
a1=±fρ2+gd2
1
4k,
b1=±(fρ2+gd2
1)λ2σ1+ (fρ2+gd2
1)µ2
4kλ ,
d1=d1, d2=(fρ τ +gd1s1), s1=s1,
s2=1
4λfρ2+gd2
11
2fτ2+gs2
1,
(33)
where σ1=A2
1A2
2and λ(<0), µ, f, g, k, d1, ρ,
s1, τ, ω, A1, A2are arbitrary constants such that
kfρ2+gd2
1<0and b1R. From Eqs. (12),
(20), (25), and (33), we obtain the exact solution of
Eq. (2) as follows:
W(x, y, t) =
±fρ2+gd2
1
4kA1cosh χλλ+A2sinh χλλ
A1sinh χλ+A2cosh χλ+µ
λ
±
(f ρ2+gd2
1)λ2σ1+(f ρ2+gd2
1)µ2
4
A1sinh χλ+A2cosh χλ+µ
λ
×e ,
(34)
where
χ=Γ(γ+ 1)
βd1xβ(fρ τ +gd1s1)yβ+ρ tβ,
ξ=Γ(γ+ 1)
βs1xβ+1
4λfρ2+gd2
11
2fτ 2+gs2
1yβ+τ tβ+ω.
Case 2 (Trigonometric function solutions):
If λ > 0, we substitute Eq.(25) with Eqs.(11) and (15)
into Eq.(22), so that the left-hand side of Eq.(22) be-
comes a polynomial in ϕ(χ)and ψ(χ). Setting all of
the coefficients of this resulting polynomial to zero,
we obtain the following system of nonlinear algebraic
equations in λ, µ, ω, ρ, τ, a0, a1, b1, d1, s1,and s2:
ϕ3: 2 f λ4ρ2A4
1a1+ 4 fλ4ρ2A2
1A2
2a1
+ 2 fλ4ρ2A4
2a1+ 2 gλ4A4
1a1d2
1
+ 4 gλ4A2
1A2
2a1d2
1+ 2 gλ4A4
2a1d2
1
+ 2 kλ4A4
1a3
1+ 4 kλ4A2
1A2
2a3
1
+ 2 kλ4A4
2a3
14fλ2µ2ρ2A2
1a1
4fλ2µ2ρ2A2
2a14gλ2µ2A2
1a1d2
1
4gλ2µ2A2
2a1d2
14kλ2µ2A2
1a3
1
4kλ2µ2A2
2a3
1+ 6 kλ3A2
1a1b2
1
+ 6 kλ3A2
2a1b2
1+ 2 fµ4ρ2a1
+ 2 gµ4a1d2
1+ 2 kµ4a3
16kλ µ2a1b2
1= 0,
ϕ2: 6 kλ4A4
1a0a2
1+ 12 kλ4A2
1A2
2a0a2
1
+ 6 kλ4A4
2a0a2
1fλ3µ ρ2A2
1b1
fλ3µ ρ2A2
2b1gλ3µ A2
1b1d2
1
gλ3µ A2
2b1d2
112 kλ2µ2A2
1a0a2
1
12 kλ2µ2A2
2a0a2
1+ 6 kλ3A2
1a0b2
1
+ 6 kλ3A2
2a0b2
1+fλ µ3ρ2b1
+gλ µ3b1d2
1+ 6 kµ4a0a2
1
4kλ2µ b3
16kλ µ2a0b2
1= 0,
ϕ2ψ: 2 fλ4ρ2A4
1b1+ 4 fλ4ρ2A2
1A2
2b1
+ 2 fλ4ρ2A4
2b1+ 2 gλ4A4
1b1d2
1
+ 4 gλ4A2
1A2
2b1d2
1+ 2 gλ4A4
2b1d2
1
+ 6 kλ4A4
1a2
1b1+ 12 kλ4A2
1A2
2a2
1b1
+ 6 kλ4A4
2a2
1b14fλ2µ2ρ2A2
1b1
4fλ2µ2ρ2A2
2b14gλ2µ2A2
1b1d2
1
4gλ2µ2A2
2b1d2
112 kλ2µ2A2
1a2
1b1
12 kλ2µ2A2
2a2
1b1+ 2 kλ3A2
1b3
1
+ 2 kλ3A2
2b3
1+ 2 fµ4ρ2b1
+ 2 gµ4b1d2
1+ 6 kµ4a2
1b1
2kλ µ2b3
1= 0,
ϕ: 2 fλ5ρ2A4
1a1+ 4 fλ5ρ2A2
1A2
2a1
+ 2 fλ5ρ2A4
2a1+ 2 gλ5A4
1a1d2
1
+ 4 gλ5A2
1A2
2a1d2
1+ 2 gλ5A4
2a1d2
1
fλ4τ2A4
1a12fλ4τ2A2
1A2
2a1
fλ4τ2A4
2a1gλ4A4
1a1s2
1
2gλ4A2
1A2
2a1s2
1gλ4A4
2a1s2
1
+ 6 kλ4A4
1a2
0a1+ 12 kλ4A2
1A2
2a2
0a1
+ 6 kλ4A4
2a2
0a14fλ3µ2ρ2A2
1a1
4fλ3µ2ρ2A2
2a14gλ3µ2A2
1a1d2
1
4gλ3µ2A2
2a1d2
1+ 2 fλ2µ2τ2A2
1a1
+ 2 fλ2µ2τ2A2
2a1+ 2 gλ2µ2A2
1a1s2
1
+ 2 gλ2µ2A2
2a1s2
1+ 6 kλ4A2
1a1b2
1
+ 6 kλ4A2
2a1b2
112 kλ2µ2A2
1a2
0a1
12 kλ2µ2A2
2a2
0a12λ4A4
1a1s2
4λ4A2
1A2
2a1s22λ4A4
2a1s2
+ 2 fλ µ4ρ2a1+ 2 gλ µ4a1d2
1
fµ4τ2a1gµ4a1s2
16kλ2µ2a1b2
1
+ 6 kµ4a2
0a1+ 4 λ2µ2A2
1a1s2
+ 4 λ2µ2A2
2a1s22µ4a1s2= 0,
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ϕψ :3fλ4µ ρ2A4
1a16fλ4µ ρ2A2
1A2
2a1
3fλ4µ ρ2A4
2a13gλ4µ A4
1a1d2
1
6gλ4µ A2
1A2
2a1d2
13gλ4µ A4
2a1d2
1
+ 12 kλ4A4
1a0a1b1+ 24 kλ4A2
1A2
2a0a1b1
+ 12 kλ4A4
2a0a1b1+ 6 fλ2µ3ρ2A2
1a1
+ 6 fλ2µ3ρ2A2
2a1+ 6 gλ2µ3A2
1a1d2
1
+ 6 gλ2µ3A2
2a1d2
112 kλ3µ A2
1a1b2
1
12 kλ3µ A2
2a1b2
124 kλ2µ2A2
1a0a1b1
24 kλ2µ2A2
2a0a1b13fµ5ρ2a1
3gµ5a1d2
1+ 12 kλ µ3a1b2
1
+ 12 kµ4a0a1b1= 0,
ψ:fλ5ρ2A4
1b1+ 2 fλ5ρ2A2
1A2
2b1
+fλ5ρ2A4
2b1+gλ5A4
1b1d2
1
+ 2 gλ5A2
1A2
2b1d2
1+gλ5A4
2b1d2
1
fλ4τ2A4
1b12fλ4τ2A2
1A2
2b1
fλ4τ2A4
2b1gλ4A4
1b1s2
1
2gλ4A2
1A2
2b1s2
1gλ4A4
2b1s2
1
+ 6 kλ4A4
1a2
0b1+ 12 kλ4A2
1A2
2a2
0b1
+ 6 kλ4A4
2a2
0b1+ 2 fλ2µ2τ2A2
1b1
+ 2 fλ2µ2τ2A2
2b1+ 2 gλ2µ2A2
1b1s2
1
+ 2 gλ2µ2A2
2b1s2
1+ 2 kλ4A2
1b3
1
+ 2 kλ4A2
2b3
112 kλ3µ A2
1a0b2
1
12 kλ3µ A2
2a0b2
112 kλ2µ2A2
1a2
0b1
12 kλ2µ2A2
2a2
0b12λ4A4
1b1s2
4λ4A2
1A2
2b1s22λ4A4
2b1s2
fλ µ4ρ2b1gλ µ4b1d2
1
fµ4τ2b1gµ4b1s2
1+ 6 b3
1λ2kµ2
+ 12 kλ µ3a0b2
1+ 6 kµ4a2
0b1
+ 4 λ2µ2A2
1b1s2+ 4 λ2µ2A2
2b1s2
2µ4b1s2= 0,
ϕ0:fλ4τ2A4
1a02fλ4τ2A2
1A2
2a0
fλ4τ2A24a0gλ4A4
1a0s2
1
2gλ4A2
1A2
2a0s2
1gλ4A4
2a0s2
1
+ 2 kλ4A4
1a3
0+ 4 kλ4A2
1A2
2a3
0
+ 2 kλ4A4
2a3
0fλ4µ ρ2A2
1b1
fλ4µ ρ2A2
2b1gλ4µ A2
1b1d2
1
gλ4µ A2
2b1d2
1+ 2 fλ2µ2τ2A2
1a0
+ 2 fλ2µ2τ2A2
2a0+ 2 gλ2µ2A2
1a0s2
1
+ 2 gλ2µ2A2
2a0s2
1+ 6 kλ4A2
1a0b2
1
+ 6 kλ4A2
2a0b2
14kλ2µ2A2
1a3
0
4kλ2µ2A2
2a3
02λ4A4
1a0s2
4λ4A2
1A2
2a0s22λ4A4
2a0s2
+fλ2µ3ρ2b1+gλ2µ3b1d2
1
fµ4τ2a0gµ4a0s2
14b3
1λ3kµ
6kλ2µ2a0b2
1+ 2 kµ4a3
0+ 4 λ2µ2A2
1a0s2
+ 4 λ2µ2A2
2a0s22µ4a0s2= 0.
(35)
Solving the above algebraic system using the Maple
package program, we get the following results:
Result 1
λ=λ, µ = 0, ω =ω, ρ =ρ, τ =τ, a0= 0,
a1=±fρ2+gd2
1
k, b1= 0, d1=d1,
d2=(fρ τ +gd1s1), s1=s1,
s2=fλ ρ2+gλ d2
11
2fτ21
2gs2
1,
(36)
where λ(>0), f, g, k, d1, ρ, s1, τ, ω are arbitrary
constants such that kfρ2+gd2
1<0. From Eqs.
(14), (20), (25), and (36), we get the solution of Eq.
(2) as follows:
W(x, y, t) = ±fρ2+gd2
1
k
×
A1cos χλλA2sin χλλ
A1sin χλ+A2cos χλ
×e,
(37)
where A1, A2re arbitrary constants and
χ=Γ(γ+ 1)
βd1xβ(fρτ +gd1s1)yβ+ρtβ
ξ=Γ(γ+ 1)
β
×s1xβ+fλρ2+gλ d2
11
2fτ 21
2gs2
1yβ+τtβ+ω.
Result 2
λ=kb2
1
σ2fρ2+gd2
1, µ = 0, ω =ω, ρ =ρ,
τ=τ, a0= 0, a1= 0, b1=b1, d1=d1,
d2=(fρ τ +gd1s1), s1=s1,
s2=σ2fτ2+gs2
1kb2
1
2σ2
,
(38)
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where σ2=A2
1+A2
2and f, g, k, d1, ρ, s1, τ, ω, b1,
A1, A2are arbitrary constants such that λ > 0. From
Eqs. (14), (20), (25), and (38), we obtain the exact
solution of Eq. (2) as follows:
W(x, y, t) = b1
A1sin χλ+A2cos χλ×e,
(39)
where
χ=Γ(γ+ 1)
βd1xβ(fρ τ +gd1s1)yβ+ρ tβ,
ξ=Γ(γ+ 1)
β
×s1xβσ2fτ2+gs2
1kb2
1
2σ2
yβ+τ tβ+ω.
Result 3
λ=λ, µ =µ, ω =ω, ρ =ρ, τ =τ, a0= 0,
a1=±fρ2+gd2
1
4k,
b1=±fρ2+gd2
1λ2σ2(fρ2+gd2
1)µ2
4kλ ,
d1=d1, d2=(fρ τ +gd1s1), s1=s1,
s2=λ
4fρ2+gd2
11
2fτ2+gs2
1,
(40)
where σ2=A2
1+A2
2and λ(>0), µ, f, g, k, d1, ρ,
s1, τ, ω, A1, A2are arbitrary constants such that
kfρ2+gd2
1<0and b1R. From Eqs. (14),
(20), (25), and (40), we obtain the exact solution of
Eq. (2) as follows:
W(x, y, t)
=±fρ2+gd2
1
4k
×
A1cos χλλA2sin χλλ
A1sin χλ+A2cos χλ+µ
λ
±(fρ2+gd2
1)λ2σ2(fρ2+gd2
1)µ2
4
A1sin χλ+A2cos χλ+µ
λ×e
(41)
where
χ=Γ(γ+ 1)
βd1xβ(fρ τ +gd1s1)yβ+ρ tβ,
ξ=Γ(γ+ 1)
β
×s1xβ+λ
4fρ2+gd2
11
2fτ 2+gs2
1yβ+τ tβ+ω.
Case 3 (Rational function solutions): If λ= 0,
we substitute Eq.(25) with Eqs.(11) and (17) into
Eq.(22), so that the left-hand side of Eq. Eq.(22) be-
comes a polynomial in ϕ(χ)and ψ(χ). Setting all of
the coefficients of this resulting polynomial to zero,
we obtain the following system of nonlinear algebraic
equations in µ, ω, ρ, τ, a0, a1, b1, d1, s1,and s2:
ϕ3: 8 f µ2ρ2A2
2a18fµ ρ2A2
1A2a1
+ 2 fρ2A4
1a1+ 8 gµ2A2
2a1d2
1
8gµ A2
1A2a1d2
1+ 2 gA4
1a1d2
1
+ 8 kµ2A2
2a3
18kµ A2
1A2a3
1
+ 2 kA4
1a3
112 kµ A2a1b2
1
+ 6 kA2
1a1b2
1= 0,
ϕ2: 24 kµ2A2
2a0a2
124 kµ A2
1A2a0a2
1
+ 6 kA4
1a0a2
1+ 2 fµ2ρ2A2b1
fµ ρ2A2
1b1+ 2 gµ2A2b1d2
1
gµ A2
1b1d1212 kµ A2a0b2
1
+ 6 kA2
1a0b2
14kµ b3
1= 0,
ϕ2ψ: 8 f µ2ρ2A2
2b18fµ ρ2A2
1A2b1
+ 2 fρ2A4
1b1+ 8 gµ2A2
2b1d2
1
8gµ A2
1A2b1d2
1+ 2 gA4
1b1d2
1
+ 24 kµ2A2
2a2
1b124 kµ A2
1A2a2
1b1
+ 6 kA4
1a2
1b14kµ A2b3
1
+ 2 kA2
1b3
1= 0,
ϕ:4fµ2τ2A2
2a1+ 4 fµ τ 2A2
1A2a1
fτ2A4
1a14gµ2A2
2a1s2
1
+ 4 gµ A2
1A2a1s2
1gA4
1a1s2
1
+ 24 kµ2A2
2a2
0a124 kµ A2
1A2a2
0a1
+ 6 kA4
1a2
0a18µ2A2
2a1s2
+ 8 µ A2
1A2a1s22A4
1a1s2= 0,
ϕψ :12 fµ3ρ2A2
2a1+ 12 fµ2ρ2A2
1A2a1
3fµ ρ2A4
1a112 gµ3A2
2a1d2
1
+ 12 gµ2A2
1A2a1d2
13gµ A4
1a1d2
1
+ 48 kµ2A2
2a0a1b148 kµ A2
1A2a0a1b1
+ 12 kA4
1a0a1b1+ 24 kµ2A2a1b2
1
12 kµ A2
1a1b2
1= 0,
ψ:4fµ3ρ2A2b1+ 2 fµ2ρ2A2
1b1
4fµ2τ2A2
2b1+ 4 fµ τ 2A2
1A2b1
fτ2A4
1b14gµ3A2b1d2
1
+ 2 gµ2A2
1b1d2
14gµ2A2
2b1s2
1
+ 4 gµ A2
1A2b1s2
1gA4
1b1s2
1
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+ 24 kµ2A2
2a2
0b124 kµ A2
1A2a2
0b1
+ 6 kA4
1a2
0b1+ 24 kµ2A2a0b2
1
12 kµ A2
1a0b2
1+ 8 kµ2b3
1
8µ2A2
2b1s2+ 8 µ A2
1A2b1s2
2A4
1b1s2= 0,
ϕ0:4fµ2τ2A2
2a0+ 4 fµ τ 2A2
1A2a0
fτ2A4
1a04gµ2A2
2a0s2
1
+ 4 gµ A2
1A2a0s2
1gA4
1a0s2
1
+ 8 kµ2A2
2a3
08kµ A2
1A2a3
0
+ 2 kA4
1a3
08µ2A2
2a0s2
+ 8 µ A2
1A2a0s22A4
1a0s2= 0.
(42)
Solving the above algebraic system using the Maple
package program, we get the following results.
Result 1
µ= 0, ω =ω, ρ =ρ, τ =τ, a0= 0,
a1=±fρ2+gd2
1
k, b1= 0, d1=d1,
d2=(fρ τ +gd1s1), s1=s1,
s2=1
2fτ2+gs2
1,
(43)
where f, g, k, d1, ρ, s1, τ, ω are arbitrary constants
such that kfρ2+gd2
1<0. From Eqs. (16), (20),
(25), and (43), we obtain the exact solution of Eq. (2)
as follows:
W(x, y, t) = ±f ρ2+gd2
1
kA1
A1χ+A2×e,(44)
where A1, A2are arbitrary constants and
χ=Γ(γ+ 1)
βd1xβ(fρ τ +gd1s1)yβ+ρ tβ,
ξ=Γ(γ+ 1)
βs1xβ1
2fτ2+gs2
1yβ+τ tβ+ω.
Result 2
µ= 0, ω =ω, ρ =ρ, τ =τ, a0= 0, a1= 0,
b1=±fρ2+gd2
1
kA1, d1=d1,
d2=(fρ τ +gd1s1), s1=s1,
s2=1
2fτ2+gs2
1,
(45)
where f, g, k, d1, ρ, s1, τ, ω, A1are arbitrary con-
stants such that kfρ2+gd2
1<0. From Eqs. (16),
(20), (25), and (45), the solution of Eq. (2) is:
W(x, y, t) = ±f ρ2+gd2
1
kA1
A1χ+A2×e,(46)
where A2is an arbitrary constant and
χ=Γ(γ+ 1)
βd1xβ(fρ τ +gd1s1)yβ+ρ tβ,
ξ=Γ(γ+ 1)
βs1xβ1
2fτ2+gs2
1yβ+τ tβ+ω.
Result 3
µ= 0, ω =ω, ρ =ρ, τ =τ, a0= 0,
a1=±1
2fρ2+gd2
1
k, b1=a1A1,
d1=d1, d2=(fρ τ +gd1s1), s1=s1,
s2=1
2fτ2+gs2
1,
(47)
where f, g, k, d1, ρ, s1, τ, ω, A1are arbitrary con-
stants such that kfρ2+gd2
1<0. From Eqs. (16),
(20), (25), and (47), we obtain the exact solution of
Eq. (2) as follows:
W(x, y, t) = ±f ρ2+gd2
1
kA1
A1χ+A2×e,(48)
where A2is arbitrary constant and
χ=Γ(γ+ 1)
βd1xβ(fρ τ +gd1s1)yβ+ρ tβ,
ξ=Γ(γ+ 1)
βs1xβ1
2fτ2+gs2
1yβ+τ tβ+ω.
Result 4
µ=fρ2+gd2
1A2
1+ 4 kb2
1
2A2fρ2+gd2
1, ω =ω, ρ =ρ,
τ=τ, a0= 0, a1=±1
2fρ2+gd2
1
k,
b1=b1, d1=d1, d2=(fρ τ +gd1s1),
s1=s1, s2=1
2fτ21
2gs2
1,
(49)
where f, g, k, d1, ρ, s1, τ, ω, b1, A1, A2are arbi-
trary constants such that kfρ2+gd2
1<0. From
Eqs. (16), (20), (25), and (49), we get the solution of
Eq. (2) as follows:
W(x, y, t) = ΦΨ +
Θe,(50)
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where
Φ = χfρ2+gd2
1A2
1+ 2 A1A2f ρ2+gd2
1+ 4 χ kb2
1,
Ψ = fρ2+gd2
1
k,
= 4 b1A2f ρ2+gd2
1,
Θ = χ2fρ2+gd2
1A2
1+ 4 A1χ A2f ρ2+gd2
1
+4fρ2+ 4 gd2
1A2
2+ 4 χ2kb2
1,
χ=Γ(γ+ 1)
βd1xβ(fρ τ +gd1s1)yβ+ρ tβ,
ξ=Γ(γ+ 1)
βs1xβ1
2fτ 2+gs2
1yβ+τ tβ+ω.
4 Graphs of Some Exact Solutions
In this section, we show graphs of some of the
exact traveling wave solutions of the truncated M-
fractional paraxial wave dynamical model in Kerr me-
dia in Eq. (2) that we obtained using the (G/G, 1/G)-
expansion method. In particular, we show the exact
solutions through 3D, 2D, and contour plots for the
following range of fractional-order values: β= 0.9,
β= 0.8,and β= 0.6. The exact traveling wave
solutions in Eq. (28) and Eq. (37) have been chosen
to demonstrate how their physical behavior changes
in terms of 3D, 2D, and contour plots when values
of the fractional-order βare altered. All figures were
obtained using the Maple software package.
In Figure 1 (Appendix), magnitudes of the exact
traveling wave solution W(x, y, t)in (28) are plotted
on the domain
D1={(x, y, t)|06x660, y = 1,and 06t630}
for the 3D plots and on the domain
D2={(x, y, t)|06x660, y = 1,and t= 1}
for the 2D graphs. In addition, contour plots, which
represent a 3D surface by plotting (x, t)contours for
a range of fixed |W|values, are also illustrated. The
following parameter values: λ=1, µ = 0,a0= 0,
b1= 0,f= 0.8,g= 2,k= 0.8,d1= 2,ρ= 0.5,
s1= 5,τ= 2,ω= 3,A1= 3,A2= 5,and γ= 1.5
are used in this figure. In particular, Figures 1 (a)-(c),
(d)-(f), and (g)-(i) (Appendix) show the 3D, 2D, and
contour graphs of magnitudes of the exact solution
W(x, y, t)in (28) calculated at β= 0.9, β = 0.8,and
β= 0.6, respectively. As can be observed from the
3D graphs of Figure 1 (Appendix), the physical be-
havior of the magnitude of solution (28) can be char-
acterized as an anti-soliton solution. In Figure 1 (Ap-
pendix), it is worth noticing that the singular point of
|W(x, t)|can be moved as the value of the fractional-
order βis changed. This is because the denomi-
nator term A1sinh χλ+A2cosh χλin
Eq. (28) can be zero depending upon the value of
β, which is embedded in χ. For the given parame-
ter values as mentioned above, the singular point is
x12.7918 when β= 0.9and t= 1 as shown in
Figure 1 (b) (Appendix).
In Figure 2 (Appendix), magnitudes of the exact
traveling wave solution W(x, y, t)in (37) are plotted
on the domain
D3={(x, y, t)|06x610, y = 1,and 06t610}
for the 3D plots and on the domain
D4={(x, y, t)|06x610, y = 1,and t= 1}
for the 2D graphs. Contour plots, which represent a
3D surface by plotting (x, t)contours for a range of
fixed |W|values, are also shown. The following pa-
rameter values: λ= 1, µ = 0,a0= 0,b1= 0,
f= 1,g= 0.5,k= 1,d1= 2,ρ= 0.1,s1= 5,
τ= 0.5,ω= 1,A1= 3,A2= 5,and γ= 0.8
are used in this figure. In particular, Figures 2 (a)-
(c), (d)-(f), and (g)-(i) (Appendix) display the 3D, 2D,
and contour plots of magnitudes of the exact solution
W(x, y, t)in (37) calculated at β= 0.9, β = 0.8,
and β= 0.6, respectively. As can be observed from
the 3D graphs of Figure 2 (Appendix), the magnitude
of solution (37) can be categorized as a singularly pe-
riodic wave solution. In Figure 2 (Appendix), it is
worth observing that the singular point of |W(x, t)|
can be changed when the value of the fractional-order
βis varied. This is because the denominator term
A1sin χλ+A2cos χλin Eq. (37) can be
zero depending upon the value of β, which appears
in χ. Specifically, the singular point of |W(x, t)|
is obtained when χλ=arctan A2
A1. For the
given parameter values as described above, some of
the singular points are, for instance, x2.1327 and
x4.0164 when β= 0.9and t= 1 as shown in
Figure 2 (b) (Appendix).
5 Conclusions
In this paper, the paraxial wave dynamical model
in Kerr media with truncated M-fractional deriva-
tives given in (2) has been symbolically solved
to obtain exact traveling wave solutions using the
(G/G, 1/G)-expansion method. Since the equation
has complex-valued solutions, we wrote exact solu-
tions as the product of a real function U(χ)and e as
shown in (20). The algebraic manipulations required
to obtain the exact solutions of the function U(χ)
were carried out using the Maple software package.
We found that exact solutions for U(χ)can be written
in terms of either hyperbolic functions, trigonometric
functions, or rational functions. From these solutions
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for U(χ), we finally obtained the exact traveling wave
solutions of the equation (2) via Eq. (20) and the trans-
formation (21).
In [38] the authors used the modified simple
equation method (MSEM) and the auxiliary equa-
tion method (AEM) to find exact solutions of the M-
fractional paraxial wave equation with Kerr media.
Their governing equation was equipped with higher-
order truncated M-fractional partial derivatives with
respect to tand x. This is slightly different from
Eq. (2) in which the composite of the truncated M-
fractional derivatives of order less than one is used.
In addition, the fractional-order βwas not inserted as
an exponent of the independent variables x, y, and
tin their traveling wave transformation. However,
the real function U(χ)of their solutions expressed in
terms of the exponential functions were found. In [39]
the truncated time M-fractional paraxial wave equa-
tion in kerr media was explored for some optical so-
lutions. The unified scheme was implemented to ob-
tain exact traveling wave solutions of the proposed
equation. As a result, the solutions were expressed in
terms of hyperbolic, trigonometric, and rational func-
tions with some free parameters. Roughly compar-
ing our results to the obtained solutions in [38], [39],
some of the exact solutions obtained in this article
have not been derived in any previous work because
equation (2) and the used method are not the same as
in the referred literature.
From our results, the 3D, 2D, and contour plots
of magnitudes of selected solutions have been plotted
for a range of values of fractional-order βusing the
Maple package in order to understand the effects of
changing the fractional-order on the physical behav-
ior of chosen solutions. From Figure 1 and Figure 2
(Appendix), an anti-soliton solution and a singularly
periodic wave solution have been found. Finally, with
the assistance of Maple, all of the exact solutions have
been verified by substituting them back into the orig-
inal equation to check their correctness. In summary,
since the (G/G, 1/G)-expansion method is an ex-
tension of the (G/G)-expansion method and its rel-
evant methods, [40], the advantage of the proposed
method is that it is more productive, efficient, and re-
liable for generating exact traveling wave solutions of
nonlinear real-world problems modeled by NPDEs.
This work could be improved by using different frac-
tional order values for the truncated M-fractional par-
tial derivatives with respect to x, y, and t. A promis-
ing future work would be to compare the fractional
equation and solutions developed in this article with
real data obtained from physical phenomena.
Acknowledgments:
The authors are grateful to anonymous referees for
their valuable comments and several constructive
suggestions, which have significantly improved this
manuscript.
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Contribution of Individual Authors to the
Creation of a Scientific Article (Ghostwriting
Policy)
Pim Malingam and Paiwan Wongsasinchai: Con-
ceptualization, data curation, funding acquisition,
investigation, methodology, software, visualization,
writing-original draft, and writing-review and editing.
Sekson Sirisubtawee (Corresponding author): Con-
ceptualization, data curation, formal analysis, in-
vestigation, methodology, project administration,
resources, supervision, validation, visualization,
writing-original draft, and writing-review and editing.
Sanoe Koonprasert: Supervision, validation, and
writing-review and editing.
Sources of Funding for Research Presented in a
Scientific Article or Scientific Article Itself
Pim Malingam (pim.m@rbru.ac.th) would like to ac-
knowledge the financial support from the Department
of Mathematics, Faculty of Science and Technology,
Rambhai Barni Rajabhat University, Chanthaburi.
Conflicts of Interest
The authors declare that they have no conflicts of in-
terest.
Creative Commons Attribution License 4.0
(Attribution 4.0 International , CC BY 4.0)
This article is published under the terms of the
Creative Commons Attribution License 4.0
https://creativecommons.org/licenses/by/4.0/deed.en
_US
Appendix
Figures described in section 4 are shown in this sec-
tion.
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(a) 3D (b) 2D (c) contour
(d) 3D (e) 2D (f) contour
(g) 3D (h) 2D (i) contour
Fig. 1: Graphs for |W(x, y, t)|where W(x, y, t)is expressed in (28) and obtained using the (G/G, 1/G)-
expansion method: (a)-(c) when β= 0.9; (d)-(f) when β= 0.8; (g)-(i) when β= 0.6.
(a) 3D (b) 2D (c) contour
(d) 3D (e) 2D (f) contour
(g) 3D (h) 2D (i) contour
Fig. 2: Graphs for |W(x, y, t)|where W(x, y, t)is expressed in (37) and obtained using the (G/G, 1/G)-
expansion method: (a)-(c) when β= 0.9; (d)-(f) when β= 0.8; (g)-(i) when β= 0.6.
WSEAS TRANSACTIONS on SYSTEMS and CONTROL
DOI: 10.37394/23203.2023.18.53
Pim Malingam, Paiwan Wongsasinchai,
Sekson Sirisubtawee, Sanoe Koonprasert
E-ISSN: 2224-2856
512
Volume 18, 2023