
and
˜z∈(z−δ, z)∩([0,1] \Θ) ,
and we apply a standard argument since Geis the
increasing function, the pair of straight lines pass
through points (˜y, Ge(˜y)), y+ 2−1z, Gey+ 2−1z
and (˜z, Ge(˜z)), z+ 2−1y, Gez+ 2−1y, respec-
tively, then the straight line passes through points
(˜y, Ge(˜y)), y+ 2−1z, Gey+ 2−1z is passing under
point (y, Ge(y)), and the straight line passes through
points (˜z, Ge(˜z)), z+ 2−1y, Gez+ 2−1y is passing
over point (z, Ge(z)) , therefore, the restriction of Ge
to (˜y, ˜z) is not concave-convex, this contradiction proves
the statement of the theorem.
Lemma 2. The Cantor-Lebesgue irregular
functions Geand Gπsatisfy the Banach condi-
tions T1.
The proof is straightforward.
Now, we are going to construct the irregular analog
of the Sierpinski carpet, a fractal-like two-dimensional
structure produced by an irregular iterated system with
a constant base of ten.
We start with a unit square [0,1] ×[0,1] and present
its points (x, y)∈[0,1] ×[0,1] in form of an expansion
in base ten
x=X
k=1,...,
ak
10k=a1
101+a2
102+a3
103+a4
104+.....
y=X
k=1,...,
bk
10k=b1
101+b2
102+b3
103+b4
104+......
We assume that abscissa and ordinate axes govern by
numbers eand π, respectively. A two-dimensional irreg-
ular Cantor set Ce,π ([0,1]) is constructed by an iter-
ative procedure of deleting squares, whose coordinates
expressed in the base ten do not both have the respec-
tive index kdigits of respective numbers eand π, respec-
tively (x, y)∈[0,1] ×[0,1]. The first deleted square is
2
10 ,3
10 ×3
10 ,4
10 , next we delete 99 squares governing
by 1 and 1 from eand π, respectively. The process is
infinite removing squares, and as a result, we obtain a
fractal irregular two-dimensional set, which we called a
two-dimensional irregular Cantor set Ce,π ([0,1]).
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References
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DOI: 10.37394/232020.2023.3.5