On Generic Automorphisms
ERMEK NURKHAIDAROV
Department of Mathematics
Pennsylvania State University
Mont Alto, PA 17237
USA
Abstract: In this article we investigate generic automorphisms of countable models. Hodges et al. 1993 intro-
duces the notion of SI (small index) generic automorphisms. They used the existence of small index generics to
show the small index property of the model. Truss 1989 defines the notion of Truss generic automorphisms. An
automorphism fof Mis called Truss generic if its conjugacy class is comeagre in the automorphism group of M.
We study the relationship between these two types of generic automorphisms. We show that either the countable
random graph or a countable arithmetically saturated model of True Arithmetic have both SI generic and Truss
generic automorphisms. We prove that the dense linear order has the small index property and Truss-generic auto-
morphisms but it does not have SI generic automorphisms. We also construct an example of a countable structure
which has SI generics but it does not have Truss generics.
Key-Words: The small index property, countable models, dense linear order, generic automorphism, random
graph, True Arithmetic, comeagre conjugacy class.
Received: March 14, 2023. Revised: October 13, 2023. Accepted: November 14, 2023. Published: January 26, 2024.
1 Introduction
Throughout this paper Mis to be a countable infi-
nite model. We can consider its automorphism group
Aut(M)as a topological group by letting the stabiliz-
ers of finite subsets of Mbe the basic open subgroups.
We will use the notation G=Aut(M). If AM
we write
GA={gG:g(a) = afor all aA},
so GAis the pointwise stabilizer of A.
The paper [1] introduces the following definition
of generic automorphism.
Definition 1. [1] An automorphism fof Mis called
Truss generic if its conjugacy class [f]G={fg=
g1fg :gG}is comeagre in G.
A subgroup Hof Gis said to have small index in G
if |G:H|<2ω, and large otherwise. If aM, then
there is a bijection between the set of the right cosets
of Gawith {g(a) : gG}. Hence Ga, and so any
open subgroup of G, has small index in G. We say
that Mhas the small index property if the converse
holds: that is, every subgroup HGof small index
is open in G.
If Ghas the small index property, then the topol-
ogy on Gcan be recovered from its abstract group
structure. This has applications in reconstructing a
structure from its automorphism group.
The paper [2] introduces the notion of SI generic
automorphisms, which are used to show that Mhas
the small index property.
Definition 2. [2] A base for Mis a set B(M)of sub-
sets of Msatisfying:
1. GAis open in Gfor all AB(M),
2. if AB(M)and gGthen g(A)B(M).
Definition 3. [2] Let B(M)be a base for M, and let
0< n < ω. We say that (g1, . . . , gn)Gnis B(M)-
automorphism, if the following hold.
1. If AB(M)then
{GB:ABB(M), gi(B) = Bfor all in}
is a base of open neighborhoods of 1 in G.
2. Let AB(M)be such that gi(A) = A, 1i
n. Let BB(M), A B, and let hiAut(B)
extend gi|A(1in). Then there is αGA
such that gα
i=α1giαextends hi(1in).
If it is needed one can add extra requirements on
automorphisms (g1, . . . , gn)in Definition 3. For ex-
ample, when working with models of Peano Arith-
metic, [3] defines (g1, . . . , gn)Gnto be B(M)-
automorphism with additional conditions: gi|Bis ex-
istentially closed in the part 1 of the definition and
gi|Ais existentially closed in the part 2.
We will need the following property of B(M)-
automorphisms.
Lemma 4. [2] Let B(M)be a base for M, and let
(g1, . . . , gn),(h1, . . . , hn)be B(M)-automorphisms
(0< n < ω). Let BB(M)and suppose that
gi|B=hi|Bfor each in. Then there is fGB
such that gf
i=hifor all in.
Definition 5. [2] We say that Mhas SI generic au-
tomorphisms, if there exists a base B(M)for M
such that for all non-zero n<ω, the set of B(M)-
automorphisms of Gnis comeagre in Gn.
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Theorem 6. [2] If Mis a countable model with SI
generic automorphisms, then Mhas the small index
property.
The paper [2] and [4] show existence of SI generic
(and therefore the small index property) for the count-
able random graph and for ω-stable ω-categorical
structures. The paper [3] is using SI generics to
show that countable arithmetically saturated models
of Peano Arithmetic have the small index property.
In [5] it is noticed that if Mhas both SI and Truss
generic automorphisms, then they coincide (because
they both are comeagre). Hence there are four pos-
sibilities for a countable model: to have both SI and
Truss generics; to have SI but not Truss generics; to
have Truss but not SI generics; and to have neither SI
nor Truss generics.
The paper [2] shows that the countable random
graph has SI generic automorphisms and [1] proves
that the countable random graph has Truss generic au-
tomorphisms.
The paper [3] proves that if Mis a countable arith-
metically saturated model of Peano Arithmetic then
Mhas SI generic automorphisms. The paper [5]
shows that if Mis a countable arithmetically saturated
model of True Arithmetic then Mhas Truss generics.
Hence we have the following result:
Example 7. Let Mbe either the countable random
graph or a countable arithmetically saturated model
of True Arithmetic. Then Mhas both SI generic and
Truss generic automorphisms.
It is an open question whether there exists a count-
able arithmetically saturated model of Peano Arith-
metic which does not have Truss generic automor-
phisms. The paper [5] shows that existence of Truss-
generics for arithmetically saturated models of Peano
Arithmetic is very closely tied to Hedetniemi’s Con-
jecture a well known open conjecture in the chro-
matic theory of graphs (see for example [6]).
In [7] the notion of SI generic automorphisms is
introduced. They show that every uncountable satu-
rated structure has SI generics.
2 Dense Linear Order
It is known that the countable model of the dense lin-
ear order without end-points has the small index prop-
erty and has Truss generic automorphisms ([1], [8]).
In this section we show that such model has no SI
generic automorphisms.
Let Q, <be the countable model of the dense
linear order without end-points. It is not difficult to
show the next lemma.
Lemma 8. Let BQbe finite and let aQ\B.
Then there exists fAut(Q)such that fGBand
f(a)=a.
The following result is not difficult either.
Lemma 9. Let BQbe such that GBis open. Then
Bis finite.
Proof. Assume not, that Bis infinite. Since GBis
open there is a finite set AQsuch that GAis a
subgroup of GB. Let bB\A. By Lemma 8 there
exists fGAsuch that f(b)=b. Hence f∈ GB,
but fGAwhich is contradiction.
Corollary 10. If Bis a base for Qand if BBthen
Bis finite.
Proof. Definition 2 requires GBto be open for every
BB. Thus by Lemma 9 every BBis finite.
Lemma 11. Let BQbe finite and let fGbe
such that f(B) = B. Then f(b) = bfor every bB.
Proof. Assume that there is b0Bsuch that f(b0)=
b0. Then there is a finite sequence b0, b1, . . . , bn1
Bsuch that
f(b0) = b1, f(b1) = b2, . . . , f (bn2) = bn1, f (bn1) =b0.
Now, if b0< b1then b0< b1< b2< . . . < bn1<
b0which is contradiction. The other case when b0>
b1is similar.
Statement 12. Q, <does not have SI generic auto-
morphisms.
Proof. Let Bbe a base for Q, <. Assume fG
is B-generic and f(A) = Afor some AB. By
Definition 3
H={GB|ABB, f(B) = B}
is a base of open neighborhoods of 1 in G. If BB
and f(B) = Bthen by Lemma 10 Bis finite and by
Lemma 11 fGB. Hence
H={GB|ABB, f GB}.
Because His a base of open neighborhoods of 1 in
G: for every finite CQthere exists BQsuch
that GCGBH. Hence for every finite CQ
there exists BBsuch that A, C B, GBH.
Therefore
ABB,fGB
B=Q.
Thus fis the identity map and the proposition fol-
lows.
The papers [1], [8] prove the next result about
the countable model of the dense linear order without
end-points.
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Statement 13. [1], [8] Q, <has the small index
property and Truss generic automorphisms.
By combining Statement 12 and Statement 13 we
conclude.
Theorem 14. Q, <has the small index property
and Truss-generic automorphisms but Q, <does
not have SI generic automorphisms.
Notice that we define SI generic for n-tuples of
automorphisms, n < ω. Similarly, we can also say
that an n-tuple (g1, g2, ..., gn)Gnis Truss generic
if the set {(gf
1, gf
2, . . . , gf
n) : fG}of its conju-
gates is a comeager in Gn. An unpublished result of
I.Hodkinson shows that Q, <has no Truss generic
2-tuples of automorphisms, by Statement 12 it does
not have SI generic 2-tuples of automorphisms either.
3 A Few Examples
As we have mentioned earlier, there are four possi-
bilities for a countable model: to have both SI and
Truss generics; to have SI but not Truss generics; to
have Truss but not SI generics; and to have neither
SI nor Truss generics. We have already found mod-
els with both SI and Truss generics: the countable
random graph or a countable arithmetically saturated
model of True Arithmetic (Example 7). In the pre-
vious chapter we have shown that Q, <has Truss-
generic automorphisms but Q, <does not have SI
generic automorphisms. In this chapter we address
the other two remaining possibilities.
Let us consider a model Q× {0,1}where each
copy of Qis the countable model of the dense lin-
ear order without end-points. An automorphism of
Q×{0,1}preserves the partition {Q×{0},Q×{1}}
and is order preserving on each copy of Q. Then ev-
ery automorphism of Q×{0,1}either fixes each copy
of Qsetwise or sends Q× {0}to Q× {1}. We no-
tice that Q× {0,1}cannot have Truss generics. By a
similar argument as in the previous section we could
show Q× {0,1}has no SI generics. Therefore we
have an example of structure with neither Truss nor
SI generics.
Example 15. Q× {0,1}has neither Truss nor SI
generic automorphisms.
Notice that in Example 15 instead of Q×{0,1}we
might have considered Q×{0,1, . . . , n 1}, n < ω.
By a similar argument Q× {0,1, . . . , n 1}, n < ω
does not have Truss generics. On the other hand Q×ω
behaves differently, Q×ωhas Truss generics. See [1]
for the details.
Our next goal is to find a model with SI generics
but without Truss generics. We need the following
result.
Theorem 16. [2] Let Mbe a countable ω-stable ω-
categorical structure. Then Mhas SI generics.
Example 17. Let Mbe a countable ω-stable ω-
categorical structure. Then M× {0,1}has SI gener-
ics but it does not have Truss generics.
Proof. Let Mbe a countable ω-stable ω-categorical
structure. Since Mis countable ω-stable ω-
categorical then M×{0,1}is also countable ω-stable
ω-categorical. By Theorem 16 M× {0,1}has SI
generics. An automorphism of M× {0,1}preserves
the partition {M× {0}, M × {1}}. Thus every au-
tomorphism of M× {0,1}either fixes each copy of
Msetwise or sends M× {0}to M× {1}. We notice
that M× {0,1}cannot have Truss generics.
[2] and [4] show that the countable random graph
has an amalgamation base. [2] proves that if Mis
countable ω-categorical with an amalgamation base
then it has SI generics. Similar argument might be
applied to R× {0,1}. It can be shown that the base
consisting of finite sets is an amalgamation base for
R× {0,1}. Since R× {0,1}is ω-categorical, then,
using the mentioned result from [2], R× {0,1}has
SI generics. R× {0,1}does not have Truss generics
by the same argument as before. Hence we obtain the
following result.
Example 18. Let Rbe the countable random graph.
Then R× {0,1}has SI generics but it does not have
Truss generics.
4 Conclusion
Two types of generic automorphisms are defined
somewhat similar. Indeed if a model has both of SI
generics and Truss generics, they coincide. If Mis ei-
ther the countable random graph or a countable arith-
metically saturated model of True Arithmetic, then M
has both SI generic and Truss generic automorphisms.
We prove that the dense linear order has the small in-
dex property and Truss-generic automorphisms but it
does not have SI generic automorphisms. We also
construct examples: a countable structures which has
SI generics but it does not have Truss generics; a
countable structure which has no SI generics but it
has Truss generics; a countable structures which has
neither SI generics nor Truss generics.
References:
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geneous structures, Proc. London Math. Soc.,
Vol.64, 1992, pp. 121–141.
[2] Hodges, W. and Hodkinson, I. and Lascar, D.
and Shelah, S., The small index property for ω-
stable ω-categorical structures and for the random
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graph, J. London Math. Soc., Vol.48, no.2, 1993,
pp. 204–218.
[3] Lascar, D., The small index property and recur-
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[4] Hrushovski, E., Extending partial automorphisms
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Contribution of Individual Authors to the
Creation of a Scientific Article (Ghostwriting
Policy)
Ermek Nurkhaidarov is the single author in the
present research, at all stages from the formulation of
the problem to the final findings and solution.
Sources of Funding for Research Presented in a
Scientific Article or Scientific Article Itself
No funding was received for conducting this study.
Conflicts of Interest
The authors have no conflicts of interest to
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article.
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