iii. [1], The interior of is
.
Theorem 3.2: Let be finite, is a subset
of , . If
and is a freezing set for , then
Proof: Let but is
an interior point of .
Now, such that , and
because of the finiteness, there exists a path
For and , the path belongs to and
for , the path belongs to .
By theorem 3.5, the path does not belong to
for and m which contradicts the
assumption.
Thus,
Theorem 3.3: [10], If
ℤⁿ such that
>, then is a minimal freezing set for
.
Proof: Let for
some proper set of .
For some index , we have . If =0,
then for the function given by
and
we have
where = and .
Now, if , then and
where
where = and
Theorem 3.4: If is a set of D.I
, U=
and a subset of is a freezing
set for
, then for the
projection function
:
→
given by
we have is a freezing set for
.
Proof: Suppose and is
defined as
then
.
Now, ()= , but is a freezing set
for , hence ,
Therefore, =.
5 Conclusion
Freezing sets are topological invariants. So, If
is a D.I, is a freezing subset for and
is an isomorphism, then is a freezing set
for . is an inclusion
function, then is a retraction and
is continuous. Moreover, if
is finite, is a subset of ,
. If and is a freezing
set for , then
Acknowledgments:
The authors are grateful to the anonymous referees
for their insightful criticism and recommendations,
which helped to strengthen the paper's presentation.
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WSEAS TRANSACTIONS on MATHEMATICS
DOI: 10.37394/23206.2023.22.42
Eman Almuhur, Eman A. Abuhijleh,
Ghada Alafifi, Abdulazeez Alkouri, Mona Bin-Asfour