
Make the forecast of 28th case. Divide the + and - of 5
variables according to (8), then find out the corresponding
column in table 1, calculate
d = Σμ = 0.7857 + 0.7143 + 0.7 + 0.7692 + 0.8125 = 3.7817
e = Σν = 0.2143 + 0.2857 + 0.3 + 0.2308 + 0.1875 = 1.2183
d* = d/(d + e) = 3.7817/(3.7817 + 1.2183) = 3.7817/5.0 =
0.7563
e* = e/(d + e) = 1.2183/(3.7817 + 1.2183) = 1.2183/5.0 =
0.2437
φ+ = 1/[1 + (e*/d*)2 ] = 1/[1 + (0.2437/0.7563)2 ] = 0.9060
φ− =1/[1 + d*/e*)2 ] = 1/[1 + (0.7563/0.2437)2 ] = 0.0941
Here φ+, φ- represent the positive and negative total
contributions of the variables. Calculate the forecast indicator
F = φ+ − φ- = 0.906 − 0.0941 = 0.8119
F > 0 show the positive departure will appear, i.e. the
pollution days T will positive, namely the pollution days T
≥
14 d. , the observed is 25 d.
Similarly, for the 29th case, F>0,the pollution days T
≥
14d.,
the observed is 23 d.
Similarly, for the 30th case, F<0,the pollution days T<14d.,
the observed is 11d.
The forecasts for 3 cases are all correct. It demonstrates that
above forecast method can be used for qualitative forecast of the
air pollution.
Acknowledgment
The support of the National Natural Science Foundation of
China (Grant No. 42275052) are gratefully acknowledged.
Thanks to prof. Hongbo Zhang and Ms Jinyu Shen for their help.
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Funded by the National Natural Science Foundation
of China (Grant No. 42275052)
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The authors equally contributed in the present
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EARTH SCIENCES AND HUMAN CONSTRUCTIONS
DOI: 10.37394/232024.2024.4.13
Hongxing Cao, Baoshan Niu, Jian Song, Hui Liu, Xiuhua Cai