A Study of Applied Reduced Differential Transform Method Using
Volterra Integral Equations in Solving Partial Differential Equations
NGUYEN MINH TUAN
Department of Mathematics, Faculty of Applied Science
King Mongkuts University of Technology North Bangkok
1518 Pracharat 1 Road,Wongsawang, Bangsue
Krungthep Mahanakorn 10800, THAILAND.
Abstract: - Nowadays, integration is one of the trending fields applied in calculus, especially in partial
differential equations. Researchers are contributing to support useful utilities to solve partial differential
equations in many kinds of methods. In this paper, we perform an application of Volterra Integral
Equations in a reduced differential transform method (we call VIE-RDTM) to find the approximate
solutions of partial differential equations. The aim is to find the approximate solutions approach to the
exact solutions with more general forms. We also extend some new results for basic functions and
compare the solutions using the reduced differential transform method and VIE-RDTM by depicting
the approximate solutions in some partial differential equations. The results showed that the VIE-RDTM
method gets the state-of-the-art general form of the solutions when the errors approach zero.
Key-Words: - Volterra Integral, Reduced Differential Transform Method, RDTM, VIE-RDTM.
Received: December 17, 2022. Revised: August 13, 2023. Accepted: September 9, 2023. Published: October 3, 2023.
1 Introduction
Recently, linear and nonlinear differential
equations have been applied in many kinds of
life, especially in the real world of computer
science, and economic problems (readers could
see more in [1, 2, 3, 4, 5]). Whilst applying in
economics looked at a newfangled approach to
reveal the nature of the solutions or control the
models in optimal problems, partial equations
are developed with more and more various types
of form, and more complete structures (shown in
[6]). The next generation of partial equations in
fractional partial equations contributed to the
development of technology, and economics.
Fractional calculus appeared as the consequence
of modern technology development and has been
expanded in different aspects of science (Shown
in [7], and [8]). Fractional calculus has rapidly
become a significant tool to control the models
in economics such as controlling price problems,
controlling options, or controlling inflation
problems. Besides that, fractional calculus also
inherited all the powerful properties from partial
differential calculus, and its application in
variation structure resembling majors (See in
[9]). However, partial differential equations have
played an important role and have not completed
the stages in the future. The development from
the partial differential equation will create the
hard roots and basic preliminaries for construing
the high floors of calculus. With the state-of-the-
art contribution of fractional partial differential
calculus, the scenario of various types of
methods have created variants to apply easier to
specific problems. The homotopy perturbation
method (see in [10]) is one of the most popular
methods applied to solve partial differential
equations. This method is useful in finding
approximate solutions to economic problems.
Similar to the homotopy perturbation method,
the Variational Iteration method is also applied
in many kinds of partial differential equations
and has got a good performance in approximate
solution results (see in paper [11]). Besides that,
the Laplace transform method is a classical
method that contributed to the development of
calculus (in paper [12]). Compared to other
methods, the Laplace method is useful in solving
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related integral equations, and some equations
about economics, and finance (see more in [6]).
The Adomian Decomposition method (see in
paper [13, 14]) is used in solving Volterra
equations, by using an iterative way, the
Adomian Decomposition method establishes the
sequences based on initial values to find
approximate solutions. In general, most of the
methods have shown good ways to directly or
indirectly illustrate the advantages and powerful
tools to find the solutions. The Reduce
Differential Transform method was introduced
by Y. Kensin et al. (See the series [15, 16, 17,
18]) and has been extended with effective
application immensely in some different
branches of partial differential equations (shown
in [19, 20, 21, 22, 23]). After that, the Reduce
Differential Transform method was expanded
into the fractional Reduce Differential
Transform method to follow the fractional
differential equations (see more in [24, 25, 26,
27, 28]). The Fractional differential derivative is
the hottest trend variation to connect the real
world and is applied in the majority of calculus.
Many books and papers have focused on
stochastic problems wherein integrals are a good
presentation with respect to the components in
stochastic optimization problems. With the hope
to combine integration and derivative, the
purpose is to find exact solutions based on initial
conditions, we applied Volterra Integral
Equations as the facility to reveal the exact
solutions. This paper considers the differential
partial equations written formed (1).
Af(x,t)+Bf(x,t)+ Mf(x,t)+Lf(x,t) = g(x,t) (1)
with the initial condition f(x,0) = h(x), where A
=
m
m
x
, and B =
n
n
x
are partial differential
derivative, M, L represent the linear or nonlinear
terms having partial derivative derivatives, and
g(x,t), h(x) are given functions. In some
fractional differential partial equations, the
constant values are hidden and the integration
will reveal the exact solution under terminal
conditions.
2 Methodology
2.1 Some Basic Definitions for Calculus
To see more details about the notations and
definitions, readers could read in [29, 30, 31, 32].
Now we would remind some related basic
reports in partial differential derivative theory.
First, we consider some definitions
Definition 1 (Gamma function) (Shown in [29],
P.8) For z C, and Re(z) > 0, the integral as
follows is defined
1
0
zt
z t e dt


(2)
Proposition 1 Base on the equation 2, we have
some specific properties related to the gamma
function using integration by part and direct
integration Γ(1) = 1:
Γ(z+1) = zΓ(z) (3)
Γ(n+1) = n! (4)
Definition 2 (Convert to Volterra Integral
equations)
To understand more clearly equation (5), we
could start practicably from the equation (6) and
(7):
0 0 0
,,
x x x
f w t dwdw x w f w t dw
(6)
2
0 0 0 0
1
,,
2!
x x x x
f w t dwdwdw x w f w t dw
(7)
Now we can embark form the first step of
equation (6): From the right-hand side, set
0,
x
h x x w f w t dt
, and we have
differentiation
0,
x
h x f w t dt
x
. After
that, integrating by x and get the equation as the
following:
00 ,
xx
h x f w t dtdw
(8)
and the equation (8) is equal the left-hand side of
the equation (6). So, the equation (6) has been
proved. Similar to the equation (7), and using the
inductive method to get the transformation
formula (5).
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2.2 Reduced Differential Transformation
Method
The reduced Differential Transformation
Method is very useful in solving linear and
nonlinear equations. This method has shown a
reduced differential transform to find the
approximate solution in the differential equation
(See more in [31, 32, 34, 35, 36, 37]. Now we
will summarize method as follows. Let’s
examine the two-variable function expressed as
f(x,t), we can write as the following
f(x,t) = w(x)v(t) (9)
Now, we can express equation (9) be formed
0 0 0
,,
i j k
kk
i j k
F x t w i x v j t H i j t







(10)
where Hk(i,j) = w(i)v(j) denotes the spectrum of
F(x,t). Then the of F(x,t) is formed by
0
1,
1
k
kk
k
tt
H x F x t
kt



(11)
where k is the order of time derivative. Then the
inverse transformation of Hk is defined by
0
0
,k
kk
k
F x t H x t t

(12)
Combine equation (11) and equation (12), we
have
0
0
0
1
,,
1
kk
kk
k
ktt
F x t F x t t t
kt




(13)
If we choose t0 = 0, from equation (13) we have
0
0
1
,,
1
kk
kk
k
ktt
F x t F x t t
kt



(14)
By applying inductive method for equation (14),
we have solution:
, lim ,
k
k
f x t F x t

(15)
2.3 Using Volterra Integral Equations -
Reduced Differential Transformation
Method
With the reduced differential transform method,
the approximate solution has been found when
approaching exact solutions. In some cases, the
solution could be expressed more generally
when it could be different by a constant. Now we
perform a new extension of this method, which
we call a Volterra Integral Equations of reduced
differential transform method (VIE-RDTM).
Let’s examine the two-variable function
expressed as f(x,t), we can write as the following
f(x,t) = w(x)v(t) (16)
we can integrate the equation (16) respect to x
from 0 to x, and then integrate the equation (16)
respect to t from 0 to t (or respect to x one more
time):
0 0 0 0
, , ,
x t x x
F x t f w t dtdw or f w t dtdw
(17)
Now, we can express equation (17) by formed
000
00
0
,
,
xij
kij
xx
k
kk
k
F x t u i x v j t dw
H i j t dw or x w H t dw





(18)
where Hk(i, j) = u(i)v(j) is the spectrum of F(x,t).
Then the fractional reduced differential
transform method of F(x,t) is formed by
0
1,
1
k
kk
k
tt
H x F x t
kt



(19)
Then the inverse transformation of Hk is defined
by
0
0
,k
kk
k
F x t H x t t

(20)
Combine equation (19) and equation (20), we
have
0
0
0
1
,,
1
kk
kk
k
ktt
F x t F x t t t
kt




(21)
If we choose t0 = 0, from equation (21) we have
0
0
1
,,
1
kk
kk
k
ktt
F x t F x t t
kt



(22)
By applying the inductive method for equation
(22):
, lim ,
k
k
f x t F x t

(23)
Finally, the solution is called from equation (22),
and equation (23) is also the original solution of
the equations.
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2.4 Basic Functions Using Transformation
Results
Now we will illustrate the fundamental function
results of the extension of composed of Volterra
Integral equations and reduced differential
transform method (VIE-RDTM) (shown in [38,
39, 40, 41, 42]). Let Tf be the transformation of
this method and g(x,t), h(x,t) are fundamentally
analytic functions. By setting Gk = Tf(g), Hk =
Tf(h) is the results of the transform after
integrating by x, we have some results as shown
in Table 1 (See more in [43],[44],[45]). We will
prove some specific terms as the following
properties:
Proposition 2
0
00
,,
1,
!
x
kxx
kk
k
f x t g w t dw then
F x g w t dw G w dw
kt


(24)
Proposition 3
00
1
1
100
,,
11
,
!
xt
kxx
kk
k
f x t g w t dw then
F x g w t dw G w dw
k t k



(25)
Proposition 4
0
1
10
1
0
,,
1,
!
1
x
kx
kk
x
k
f x t g w t dw then
t
F x g w t dw
kt
k G w dw

(26)
Proposition 5
00
0
1
0
,,
1,
!
1
xx
kx
kk
x
k
f x t g w t dw then
t
F x x w g w t dw
kt
x w k G w dw


(27)
Proposition 6
2
2
0
2
20
2
0
,,
1,
!
12
x
kx
kk
x
k
f x t g w t dw then
t
F x g w t dw
kt
k k G w dw
(28)
Proposition 7
2
2
00
2
20
2
0
,,
1,
!
12
xx
kx
kk
x
k
f x t g w t dw then
t
F x g w t dw
kt
k k G w dw

(29)
Proposition 8
0
00
,,
xm
k
x
k k r
r
f x t t g w t dw then
F x r m G w dw

(30)
3 Numerical Results
In this section, we illustrate the solutions by
using Volterra Integral Equation-Reduced
Differential Transform Method compared to the
solutions using the Reduced Differential
Transform Method ([46, 47, 48]) through the
examples as the following:
Example 1 We consider the Black-Scholes
equation (See in [6]) formed
2
2
2
,,
0
f x t f x t
x
tx


(31)
satisfy the terminal condition f(x,0) = x2.
Using RDTM method Applying RDTM method
(see more detailed in [49]), from equation (31),
we turn the equation (31) into new form
2
2
12
,
1
11
kk
f x t
k H x x H x
kx


(32)
Using the condition, we have the following
equations (33), (34):
H0(x)=x2; H1(x)=2x2 (33)
H2(x)=2x2; H1(x)=
4
3
x2 (34)
By inductive method, we have the specific
solution as (35).
23
222
, 1 2 2! 3!
tt
f x t x t




(35)
This result approach to exact solution
u(x,t) = x2 e2t .
Using VIE-RDTM method: From equation (31),
we integrate both sides of the equation using
integration by part respect to x from 0 to x, and
then integration respect to t from 0 to t to turn
(31) into Volterra integration equation, we
rewrite the equation (31) as equation (36):
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2
00
00
, , 2 ,
2,
xx
xx
f w t dw x f x t xf x t d
x
d w dwd







(36)
Apply transformation in Table 1 by using VIE-
RDTM, from equation (36), we have the new
form of equation (37):
2
11
0
1
0
12
2
x
k k k
x
k
H w dw x H x xH x
k
H w dw
k




(37)
From (37), we will construe the inductive step by
counting values H1, H2, H3, ...
H0(x)=x2; H1(x)=2x2 (38)
H2(x)=2x2; H1(x)=
4
3
x2 (39)
We got the exact solution using the VIE-RDTM
method using the formula equation:
23
222
, 1 2 2! 3!
tt
f x t x t




(40)
Finally, the solution in equation (40) lead to
another form of exact solution f(x,t) = x2e2t , and
is illustrated in Figure 1 and Figure 2.
Example 2 In the second example, a partial
differential equation for a European option is
given (See in [6]) by:
2
2
2
, , , 0
f x t f x t f x t
xx
t x x
(41)
subject to initial condition u(x,0) = x2.
Using RDTM method Applying the
transformation using RDTM, we have equation
(42):
2
2
12
1
1
k k k
H x x H x x H x
k x x





(42)
By using inductive step, we have equation (43),
(44):
H0(x) = x2; H1(x) = 4x2 (43)
H2(x) = 8x2; H3(x) = 32x2/2; H4(x) = 64x2/3;···
(44)
Finally, using RDTM, we have the solution
shown in (45):
23
244
, 1 4 2! 3!
tt
f x t x t




. (45)
The equation (45) will lead to the exact solution
f(x,t) = x2e4t .
Using VIE-RDTM method From equation (41),
integrating both sides respect to x then applied
the formula we have equation 46:
2
0
00
,,
3 , ,
x
xx
x w f x t dw x f x t
t
wf w t dw x w f w t dw


(46)
2
0
0
0
3
1
x
kk
x
kx
k
x H x wH w dw
x w H w dw kx w H w dw







(47)
We will construe the inductive values as
equation (48), (49):
H0 = x3/3; H1 = 4x3/3 (48)
H2 = 8x2; H3 = 32x2/2; H4 = 64x2/3; ··· (49)
Finally, we have the exact solution using VIE-
RDTM as equation (50):
23
244
, 1 4 2! 3!
tt
f x t x t




. (50)
The equation (50) will lead to the exact solution
f(x,t) = x2e4t and will be graphed in Figure 3 and
Figure 4.
Example 3 In this example, a fractional
diffusion PDE is to demonstrate the relation
between variable stable distribution (See in [6])
given by
22
,,
,0
f x t f x t
t x t f x t t
tx


(51)
subjected to the term condition u(x,0) = 1, and
,0u x x
t
.
Using RDTM method Apply RDTM method,
we have the form:
(k +1)Hk+1 = x
t
Hk+1 −Hk−1 +δ(k −1) (52)
By iterative method, we have the following
terms in equation (53):
H0(x) = 1; H1(x) = x; H2(x) = 0 (53)
H3(x) = x/2; H4(x)= 0 (54)
H5(x) = x/8; H6(x)= 0 (55)
The solution of equation (51) has form:
24
, 1 1 28
tt
f x t xt


. (56)
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The equation (56) will be convergent to exact
solution
2
2
,1
t
f x t xte
.
Using VIE-RDTM method: From equation
(51), integrating both sides using integration by
part respect to x, we have
00
22
00
, , ,
,
xx
xx
t f w t dw xf x t f w t d
t
t f w t dw t dw




(57)
Applying transformation using Table 1 and we
have equation (58):
1
0
00
00
0
11
1
11
x
kk
k
x
kr
r
k
xx
kr
r
k H w dw xH x k
r H w dw
r H w dw k dw



(58)
Applying inductive for equation (58), we have
equation (59), (60), (61):
H0(x) = 1; H1(x) = x. (59)
H2(x) = 0; H3(x)= x/2; H4(x)= 0. (60)
H5(x) = x/8; H6(x) = 0. (61)
Similarly, using VIE-RDTM we have the exact
solution expressed as equation (62):
24
, 1 1 2 8!
tt
f x t xt


(62)
The result will lead to exact solution form
2
2
,1
t
f x t xte
and has been depicted in
Figure 5 and Figure 6.
Example 4 In this example, we illustrate a
diffusion process defined by the Burgers
equation as the following (see in [9]):
,,
1 , 0
f x t f x t
f x t
tx


(63)
satisfy the initial condition: u(x,0) = x−1.
Using RDTM method
Similarly, from equation (63), we have
1
0
1
1
k
k k k r r
r
H x x H H H
kx





(64)
By taking inductive for the terms, we have
equation (65), (66):
H1(x) = −x; H2(x) = x; (65)
H3(x) = −x; H4 = x; ··· (66)
Finally, we have the exact solution using the
RDTM method shown as equation (67):
2 3 4
, 1 1f x t x t t t t
(67)
The equation (67) will be convergent to the exact
solution
,1
1
x
f x t t
.
Using VIE-RDTM method From equation (63),
we integrate both sides:
0
0
,,
,,
x
x
f w t dw f x t
t
f w t f w t dw
x

(68)
Applied transformation by using RDTM, we
have equation (69):
0
0
1
,
k
x
x
Hx
f w t dw
tk
H w f w dw
x





(69)
Counting the terms by an inductive method, we
have equation (70), (71):
H0(x) = x−1; H1(x) = −x; H2(x) = x. (70)
H3(x) = −x; H4(x) = x; ··· (71)
Finally, we have the exact solution using the
VIERDTM method shown as equation (72):
2 3 4
, 1 1f x t x t t t t
(72)
The equation (72) will lead to exact solution
,1
1
x
f x t t

and delineated in Figure 7 and
Figure 8.
Example 5 In this example, we illustrate a linear
differential equation defined by the following
(see in [50]):
2 2 2
22
, , ,
4f x t f x t f x t
t x x t

(73)
satisfy the initial condition:
u(x,0) = x2; ut(x,0) = ex.
Using VIE-RDTM method From equation (73),
we integrate both sides:
2
2
0 0 0
,,
4,
x x x
f w t f t
dw f x t dw
tt



(74)
Applied transformation by using RDTM, we
have equation (69):
00
0
4 1 2
1
xx
kk
x
k
k k H w dw H t
k H w dw


(75)
Counting the terms by an inductive method, we
have equation (70), (71):
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H0(x) = x2; H1(x) = ex; H2(x) = 1/4 − 3ex/8. (76)
H3(x) = 13ex/96; H4(x) = − 17ex /512; ··· (77)
Finally, we have the exact solution using the
RDTM method shown as equation (72):
2 3 4
2 3 4
,
41 ...
5 4 32 384 6144
41 ...
5 2 6 24
xx
x
x
f x t e e t
t t t t
e
t t t
et







(78)
The equation (78) will lead to exact solution
2
24
4
,45
t
xxt
t
f x t x e e



. compared to
[50] and performed in Figure 9 and Figure 10.
4 Conclusion
Partial differential calculus is usefully applied in
many fields of applied mathematics and
technology science. It is also applied in a huge
number of branches of finance, physics,
viscoelastic mechanics, or economics [51, 52]).
In this paper, we suggested the combination of
integration and differential method, and this
method showed the most convenient shortcut to
find the exact solution. The method is omitting
the derivative terms and replacing them with
reduced terms and integration. The method has
performed successfully to get the analytic
solution approaching the exact solution.
Acknowledgement:
The author Nguyen Minh Tuan acknowledges
the comments of anonymous referees, which
improved the manuscript qualitatively, and is
indebted to the editor for illuminating advice and
valuable discussions
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Contribution of Individual Authors to the
Creation of a Scientific Article (Ghostwriting
Policy)
Nguyen Minh Tuan carried out all the content of
the paper consisting of conceptualization, data
curation, investigation, formal analysis,
methodology, software, visualization, writing-
original draft, and writing review and editing.
Please visit Contributor Roles Taxonomy (CRediT)
that contains several roles:
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Alternatively, the following text will be published:
The authors equally contributed in the present
research, at all stages from the formulation of the
problem to the final findings and solution.
Figure 1: The first example in 2D
Figure 2: The first example in 3D
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Figure 3: The second example in 2D
Figure 4: The second example in 3D
Figure 5: The third example in 2D
Figure 6: The third example in 3D
Figure 7: The fourth example in 2D
Figure 8: The fourth example in 3D
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Figure 9: The fifth example in 2D
Figure 10: The fifth example in 3D
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No funding was received for conducting this study.
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The authors have no conflicts of interest to declare
that are relevant to the content of this article.
EQUATIONS
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Contribution of Individual Authors to the
Creation of a Scientific Article (Ghostwriting
Policy)
Nguyen Minh Tuan carried out all the content of
the paper consisting of conceptualization, data
curation, investigation, formal analysis,
methodology, software, visualization, writing-
original draft, and writing review and editing.
Please visit Contributor Roles Taxonomy (CRediT)
that contains several roles:
www.wseas.org/multimedia/contributor-role-
instruction.pdf
Alternatively, the following text will be published:
The authors equally contributed in the present
research, at all stages from the formulation of the
problem to the final findings and solution.