of the system
v1x=1
1+e−µ1(w11 x+w12 y+w13 z−θ1),
v2y=1
1+e−µ2(w21 x+w22 y+w23 z−θ2),
v3z=1
1+e−µ3(w31 x+w32 y+w33 z−θ3).
(2)
The system (2) consist of three equations which
define the nullclines. Three nullclines can inter-
sect only in Q3.Indeed, suppose that the critical
point (x∗, y∗, z∗) locates outside Q3.Then some
coordinate, say x∗,either is negative or greater
than 1/v1.This contradicts the properties of the
sigmoidal function in the right side (recall that
the range of values of a sigmoidal function is
(0,1)). The number of intersections is finite, but
cannot be zero. A unique cross-point is possible,
as examples show.
Our intent in this paper is to clarify the follow-
ing situation. Imagine that there is a unique crit-
ical point (an equilibrium), which is not attrac-
tive. The sufficient condition for non-attractivity
is positivity of a real part of at least one char-
acteristic number λ. The characteristic numbers
can be computed for any equilibrium using the
standard analysis of the linearized equation. We
will provide the necessary information in the next
section. If a unique critical point is not attractive,
there are other attractors.
We pass to description of our results in this
direction. We provide the sufficient conditions,
in terms of the coefficients of Wand parame-
ters of the system (1), for a critical point to be
non-attractive. We construct then the examples,
where our conditions are applicable. In these ex-
amples the critical point is unique. Therefore an
attractor of more complicated structure should
exist. We have discovered them. To be more spe-
cific, our intent is to provide conditions for ex-
istence of equilibria with the characteristic num-
bers λ1∈R, λ2,3=α±βi, where α > 0, i =√−1.
2 Problem Formulation
Consider system (1), where v1=v2=v3= 1,for
simplicity.
The critical points are solutions of the system
x=1
1+e−µ1(w11 x+w12 y+w13 z−θ1)
y=1
1+e−µ2(w21 x+w22 y+w23 z−θ2),
z=1
1+e−µ3(w31 x+w32 y+w33 z−θ3).
(3)
The linearized system at a critical point
(x∗, y∗, z∗) is
u0
1=−u1+µ1w11g1u1
+µ1w12g1u2+µ1w13g1u3,
u0
2=−u2+µ2w21g2u1
+µ2w22g2u2+µ2w23g2u3,
u0
3=−u3+µ3w31g3u1
+µ3w32g3u2+µ3w33g3u3,
(4)
where
g1=e−µ1(w11 x∗+w12 y∗+w13 z∗−θ1)
[1 +e−µ1(w11 x∗+w12 y∗+w13 z∗−θ1)]2,
g2=e−µ2(w21 x∗+w22 y∗+w23 z∗−θ2)
[1 +e−µ2(w21 x∗+w22 y∗+w23 z∗−θ2)]2,
g3=e−µ3(wn1x∗+wn2y∗+w33 z∗−θ3)
[1 +e−µ3(w31 x∗+w32 y∗+w33 z∗−θ3)]2.
Properties of a critical point (x∗, y∗, z∗) are de-
scribed by the three numbers (they are called the
characteristic numbers) λ1, λ2, λ3,which can be
found from the chracteristic equation. One has
det(A−λI) = 0,(5)
where Ais 3 ×3 matrix of the coefficients of the
system (4), Iis the unity 3 ×3 matrix.
The equation (5) is complicated, since it re-
quires computation of the partial derivatives gi
at the critical point (x∗, y∗, z∗).It can be sim-
plified, however, in this way. Observe, from (3),
that
e−µ1(w11 x∗+w12 y∗+w13 z∗−θ1)=1
x∗−1,
e−µ2(w21 x∗+w22 y∗+w23 z∗−θ2)=1
y∗−1,
e−µ3(w31 x∗+w32 y∗+w33 z∗−θ3)=1
z∗−1.
(6)
Then g1=
1
x∗−1
1
x∗2
=(1 −x∗)x∗and, similarly,
g2= (1 −y∗)y∗, g3= (1 −z∗)z∗.
The entries aij of the matrix A−λI, needed for
construction of the characteristic equation, are:
a11 =µ1w11(1 −x∗)x∗−1−λ,
a12 =µ1w12(1 −x∗)x∗,
WSEAS TRANSACTIONS on COMPUTER RESEARCH
DOI: 10.37394/232018.2022.10.6
O. Kozlovska, F. Sadyrbaev